A body of mass 3 kg is moving with speed 8 mps the body strikes with an identical body in such a way
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Answered by
0
Explanation:
By momentum conservation in Y-direction.
mv1sin30−mv22sin30=0
v1=v2
In X direction,
mu1=mv1cos30+mv2cos30
m×3=2mv1×23
v1=v2=33=3
Answered by
0
Answer:
Answer
By momentum conservation in Y-direction.
mv
1
sin30−mv
2
2sin30=0
v
1
=v
2
In X direction,
mu
1
=mv
1
cos30+mv
2
cos30
m×3=2mv
1
×
2
3
v
1
=v
2
=
3
3
=
3
.
.
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