A body of mass 3 kg is thrown vertically upwards with an initial velocity of 20m/s. what will be it's potential energy at the end of 2 s?
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Answer:
600J
Explanation:
First font out height the ball has travelled using the following equation -
h=ut-1/2gt^2 ,
where u is initial velocity
g is acceleration due to gravity(10 taken)
t is time (given in question).
Solving h comes out to be 20m.
Then use the following equation to get potential energy gained by the ball -
PE=mgh
where m is mass of the ball
g is acceleration due to gravity
h is height ( determined above)
Hehe.
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