Question

A body of mass 3 kg is under a constant force
which causes a displacement s in metres in it,
given by the relation s = 12, where t is in
seconds. Work done by the force in 2 seconds
[AIPMT-2006]
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Answer 1

Answer:

108 kgms^-1

108 J

(1 J = kgms^-1)

Explanation:

distance (or) displacement=12 m

time=2 second

mass=3 kg

Work done(J)=force×displacement

Force(N)=mass(m)×acceleration(a)

Acceleration(a)=velocity(v)/time(t)

Velocity(v)=distance(s)/time(t)

v=12/2= 6 m/s

a= 6/2 = 3 m/s^2

N= 3× 3= 9 N

work done(J)= 9 × 12=108 J