A body of mass 3 kg is under a force, which causes a displacement in it is given by S=t3/3 (in m). Find the work done by the force in first 2 seconds? , (a) 2 I, (b) 3.8 I, (c) 5.2 I, (d) 24 I
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s=3t3
⇒dtds=v=t2
⇒a=2t
w=∫fd
=0∫2mat2dt
=30∫22t3dt
=60∫2t3dt
=46[t4]02
=46×16=24J
∴workdone=24J.
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