Question

A body of mass 3 kg is under a force which causes a displacement in it .and is given by S = t square/3.work done by the force in 2 sec

Answer 1

hope this helps you in understanding the solution

Answer 2

hello friend...!!

• According to the question we should calculate the work done :

• we know, W = F X S ----(1)

F = m x a ----(2)

now substituting equation (2) in (1) gives,

W = m x a x s -----(3)

a = dv/dt

$v \: = \:( {t}^{2} \: \div 3) \times \frac{d}{dt}$
implies,

V = 2t / 3

implies,

a = 2/3 -------(4)

substituting equation (4) in (3) gives,

mass = 3 kg, t = 2 sec a = 2/3 ,
$s \: = \: {t}^{2} \div 3$
at t = 2 seconds, S = 4/3

therefore,

W = 3 X 2/3 X 4/3

W = 8/3 kg m^2 S^-2.

____________________________


hope it helps...!!!