Question

A body of mass 3 kg travels according to the law X=at +bt2+ct3 ,where a= 3m/s,b=4m/s^2,c=5m/s^3
the force acting on the body at t=2 seconds is
a)136N
b)204N
c)158N
d)68N
plz answer fast, it's urgent​

Answer 1

option is bi 204 Newton in this we can solve the problem

Answer 2

Answer:

a) F= 136N

Explanation:

Here, m=2kg

x(t)=at+bt2+ct3

υ=dx/dt=a+2bt+3ct2

a=dυ/dt=0+2b+6ct

As t=2sec,a=2b+12c=2×4+12×5=68m/s2

F=ma=3×68N=204N .