Question

a body of mass 30×10-3 kg when acted upon by a force for 5s attains a velocity of 100m/s if the same force is applied for 2 minutes on a body of mass 10 kg at rest what will be its velocity​

Answer 1

Answer:

impulse= change in momentum

f×5= 30× 100

f×120= 10000× v

here mass is in gram and time in sec

divide eq2 by eq1

24 = 10v /3

v= 7.2 m/s

Answer 2

Explanation:

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