Question

A body of mass 30 kg is thrown vertically upward with
initial speed of 30 m/s. Its total energy after 3 s will be
Zero
900 J
2700 J
13500 J​

Answer 1

13500 J​ would be the total energy after 3 seconds.

Explanation:

Given that,

Mass of the body thrown vertically upwards = 30 Kg

Initial speed = 30 m/s

To find,

Total energy after 3 seconds = ?

Procedure:

Since the body is thrown from rest, initial potential energy would be 0.

So,

Total energy after 3 secs = PE + KE

= mgh + (1/2)mv^2

= 0 + (1/2) 30 * (30)^2

= 1/2 * 30 * 900

= 1/2 * 27000

= 13,500 J

Learn more: Find the energy

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