A body of mass 30 kg is thrown vertically upward with initial speed of 30 m/s. Its total energy after 3 s will be
Answers
Answer:
13.5 kj (approx)
Explanation:
E = 1/2 mv^2
Total energy after 3 seconds will be 13.5 kJoule if A body of mass 30 kg is thrown vertically upward with initial speed of 30 m/s
Explanation:
Energy can neither be created nor destroyed.
it can be converted from one form to another form
Hence Energy at 0sec & 3 sec will be same
Energy at secs
= PE + KE
= mgh + (1/2)mv²
= 0 + (1/2)(30)(30)²
= 13500 Joule
= 13.5 kJoule
initially Potential Energy = 0
Kinetic energy = 13.5 kJoule
Total Energy = 13.5 kJoule
Energy at 3 Sec will also be 13.5 kJoule
Verification :
g = 10 m/s²
V = U + at
a = -g = - 10 m/s²
t = 3 sec
Velocity after 3 secs = 30 - (10)(3) = 0
Height after 3 sec
S = (V² - U²)/2a
=> Height = (0² - 30²)/2(10) = 45 m
Energy at 3 secs
= mgh + (1/2)mv²
= 30(10)(45) + 0
= 13500 Joule
= 13.5 kJoule
Potential Energy at 3 secs = 13.5 kJoule
Kinetic energy at 3 secs = 0
Total Energy = 13.5 kJoule
13.5 kJoule Kinetic energy converted into potential energy
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