Question

A body of mass 300 g, initially at rest, is acted upon by a force which causes it to move

a distance of 6 m in 3 s. Calculate the force applied.​

Answer 1

Answer:

The force applied is 0.4 N

Explanation:

Given :

A body of mass 300 g, initially at rest, is acted upon by a force which causes it to move  a distance of 6 m in 3 s.

To find :

the force applied

Solution :

From Newton's second law of motion,

⇒ F = ma

where

m denotes mass of the object

a denotes its acceleration

We're given the mass of the body (i.e., 300 g = 0.3 kg) and to calculate the force applied, we have to find the acceleration from the given data.

 initial velocity, u = 0

time taken, t = 3 s

distance covered, s = 6 m

Using  S = ut + 1/2 at²:

6 = 0(3) + 1/2 (a)(3)²

6 = 0 + 9a/2

9a/2 = 6

9a = 2(6)

9a = 12

a = 12/9

a = 4/3 m/s²

∴ The acceleration of the body is 4/3 m/s²

The force applied is :

F = ma

F = ( 0.3 × 4/3 ) N

F = 0.4 N