Question

A body of mass 300 gm is at rest. What force
in Newton will you have to apply to move it
through 200 cm in 10 sec.?
A) Zero
B) 12 Newton
C) 1.2 Newton
D) 0.12 Newton​

Answer 1

Answer:

12 Newton

Explanation:

in 1.2 Newton will be appalied

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Force=0.012\:N}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Mass \: of \: body(m) = 300 \: gm \\ \\ \tt: \implies Distance(s) = 200 \: cm \\ \\ \tt: \implies Time \: taken(t) = 10 \: sec \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Force \: required \: to \: move(F) =?$

• According to given question :

$\tt\circ\:Distance=\frac{200}{100}=2\:m\\\\ \tt \circ \: Mass = \frac{300}{1000} = 0.3 \: kg \\ \\ \tt \circ \:Initial \: speed = 0 \: m/s\\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies s = ut + \frac{1}{2} {at}^{2} \\ \\ \tt: \implies 2 = 0 \times 10 + \frac{1}{2 } \times a \times {10}^{2} \\ \\ \tt: \implies 2 \times 2 = 100 \times a \\ \\ \tt: \implies a = \frac{4}{100} \\ \\ \green{\tt: \implies a = 0.04 { \: m/s}^{2} } \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies Force = Mass \times Acceleration \\ \\ \tt: \implies Force = 0.3 \times 0.04 \\ \\ \green{\tt: \implies Force = 0.012 \: N} \\ \\ \green{\tt \therefore Force \: required \: is \: 0.012 \: N}$