a body of mass 300 gram kept at rest break into 2 parts due to internal force. One part of mass 200 g is found to move at a speed of 12 m/s towards east. What will be the velocity of other part?
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Momentum is conserved
Momentum before explosion = Momentum after explosion
0 = m1v1 + m2v2
0 = 0.2*12 + 0.1v
v = -2.4/0.1
v = -0.24 m/s
Velocity of other part is 0.24 m/s (= 24 cm/s) towards west.
Momentum before explosion = Momentum after explosion
0 = m1v1 + m2v2
0 = 0.2*12 + 0.1v
v = -2.4/0.1
v = -0.24 m/s
Velocity of other part is 0.24 m/s (= 24 cm/s) towards west.
dilanothomasdt:
tnks.....
You’re welcome :)
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