A body of mass 300 kg is moved through 10 m along a smooth inclined plane of angle 30'. The
work done is moving in joules is (g=9.8 ms?)
[2013 M]
a) 14. 700
b) 2450
c) 4900
d) 9800
Answers
Answered by
5
Answer:
Work done in moving the body up the inclined plane is equal to the gain in potential energy of the body.
Thus work done=mgh=mgdsinθ
=300×9.8×10×sin30
∘
=14700 J
Answered by
0
Answer:
14700 J
Explanation:
Work done in moving the body up the inclined plane is equal to the gain in potential energy of the body.
Thus work done=mgh=mgdsinθ
=300×9.8×10×sin30
∘
=14700 J
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