A body of mass 36g moves with shm of amplitude A=13 cm and period T=12s at t=0 x=+13cm find the displacement at t = 2sec
Options
1. 7.0 sec
2. 6.5 sec
3. 5.5 sec
4. 3.2 sec
Answers
Answered by
2
Answer:
Explanation:
The equation of the SHM is:-
y=Acosωt where A=13cm and
T
2π
as T=125,⇒ω=
12
2π
=
6
π
rad/s
also at t=0,y=13 as given
=y=13cos(
6
πt
) ⇒t=
π
6
cos
−1
(
13
y
)
when particle is at y=6.5 ,time is,
t
1
=
π
6
cos
−1
(
13
6.5
)=
π
6
×
3
π
=25
also when y=−6.5, time is :-
t
2
=
π
6
cos
−1
(
13
−6.5
)=
π
6
×
3
2π
=45
∴ Time difference Δt=t
2
−t
1
=(4−2)=2s
Similar questions