Question

A body of mass 3kg is dropped from. the height of 1m the kinetic energy of the body will be when it touches the ground?​

Answer 1

Answer:

approximately 30 Neutons

Answer 2

Explanation:

v^2=u^2+2gh. (u=0, g=9.8, h=1m)

v^2=0^2+2*9.8*1

v^2=0+19.6

v= √19.6

v=4.44

kinetic energy= 1÷2×mv^2

kE=1÷2×3×4.44×4.44 = 29.57