Question

A BODY OF MASS 3kg IS MOVING WITH A VELOCITY OF 5km/s. A FORCE OF 12N IS APPLIED ON IT. WHAT WILL BE ITS VELOCITY AFTER 1s.​

Answer 1

Answer:

after 1s velocity will be 9000m/s

Step-by-step explanation:

F=ma

a=F/m

a=12/3=4m/s^2

v is final velocity

u is initial velocity

t is time

a is acceleration

F is force

a=(v-u)/t

4=(v-5)/1

4=v-5

v=4+5

v=9km/s

v=9000m/s