Question

A body of mass 3kg retards uniformly from 40 m/s to 10 m/s in 10 sec .
find retarding force​

Answer 1

m = 3kg

u = 40m/s

v = 10m/s

t = 10 s

F = m × (v-u)/t = 3 × (10-40)/10

= 3× (-30)/10

= 3 × (-3)

=-9N

Answer 2

Answer:

F=-9N

Explanation:

F=ma

m (v-v0/t)

3 (10-40/10)

3 (-30)/10

-9