Question

A body of mass 3kg retards uniformly from 40m/s to 10m/s in 10s.find the retarding force.?please reply soon.....

Answer 1

Final velocity = 10m/s

Initial velocity = 40m/s

Time = 10sec

=> Acceleration = (Final velocity-Initial velocity by time)

=> a = {(10-40)÷10)}

=> a = (-30÷10) = -3

Now, force => (m×a) => {4×(-3)} N

=> -12 N (ans)