A body of mass 3kg starts falling down from rest position. After 3sec.,what will be its kinetic energy if g =10^-2 ?
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Hey!
given,
mass=3kg
u=0
t=3s
then,
v=u+gt
v=0+10*3
v=30m/s
so,
K.E=1/2mv^2
=1/2*30^2
=1/2*900
=450j
Hope it helps you
given,
mass=3kg
u=0
t=3s
then,
v=u+gt
v=0+10*3
v=30m/s
so,
K.E=1/2mv^2
=1/2*30^2
=1/2*900
=450j
Hope it helps you
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