a body of mass 4.5 kg is thrown vertically upward with an initial velocity of 15 m/s.what will be its potential energy a the end of 2s.
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S = ut + 0.5at²
= (15 m/s × 2s) + (0.5 × (-9.8 m/s²) × (2 s)²)
= 30 m - 19.6 m
= 10.4 m
Height reached by the body in 2 s is 10.4 m
Potential energy at that height is
P.E = mgh
= 4.5 kg × 9.8 m/s² × 10.4 m
= 458.64 Joule
[Note: If value of g is taken as 10 m/s² then final answer would be 450 Joule]
= (15 m/s × 2s) + (0.5 × (-9.8 m/s²) × (2 s)²)
= 30 m - 19.6 m
= 10.4 m
Height reached by the body in 2 s is 10.4 m
Potential energy at that height is
P.E = mgh
= 4.5 kg × 9.8 m/s² × 10.4 m
= 458.64 Joule
[Note: If value of g is taken as 10 m/s² then final answer would be 450 Joule]
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