Question

A body of mass 4 kg accelerated upon by a constant force, travels a distance 5m in the 1st second and a distance of 3m in the 3rd second.What is the force acting on the body?

Answer 1

Answer:

Let distance travel in 1st second, 2nd second,3rd be S

1

,S

2

and S

3

respectively .

Applying equation of motion

For t=1s

S

1

=u×t

1

+1/2at

1

2

5=u×1+1/2×a×1

2

10=2u+a (Equation1)

For t=2s

S

1

+S

2

=u×t+1/2at

2

S

1

+S

2

=u×2+1/2×a×2

2

S

1

+S

2

=2u+2a

Explanation:

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