Science, asked by sangtluangi9636, 4 months ago

a body of mass 4 kg fall from rest.
(a) what will be its velocity after 2 second?
(b) what will be its Kinetic energy during the fall at the end of 2 second?​

Answers

Answered by CrazyKitkat
3

Answer:

Given,

mass of body = 4kg

time taken =2s

we know

v=gt

v=10×4

v=40m/s

K.E= 1/4mv^2

=1/4×2×40×40= 1600 J

So, kinetic energy of body = 1600J

Hope it helps you :)


sangtluangi9636: thank you for answering my question i really really appreaciate it , but your answer was not correct .
CrazyKitkat: Ohh... M really sorry... :(
Answered by jampaiahjampi
0

Answer:

Given,

mass of body =2kg

time taken =2s

we know

v=gt

v=10×2

v=20m/s

K.E= 2

1 mv 2

=1/2×2×20×20=400J

So, kinetic energy of body =400J

Explanation:

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