Question

A body of mass 4 kg initially at rest moves under the action of an applied force 8 N on
a table with coefficient of kinetic friction 0.1 compute
[a] accleration produce on the mass
[b] Displacement produced on the mass in 10 seconds
[c] work done by the frictional force in 10 seconds.

Answer 1

Answer:

Given:

Mass(m)=4kg

Force(F)=8N

a) acceleration=?

F=ma

8=4*a

a=8/4

a=2 m/s²

b) Displacement in 10 seconds=?

initial velocity (u)=0 m/s

acceleration (a)=2 m/s²

time(t)=10 s

final velocity (v)= u+at

v=u+at

v=0+2*10

v= 20 m/s

v²-u²=2as

400-0=2*2*s

s=400/4

s=100 m

c) work done(w)=?

W=Fs

W=8*100

W=800 J