A body of mass 4 kg, initially moving straight horizontally at 3 m/s, is pushed uniformly in the same direction
of its motion and its velocity becomes 9 m/s in 2 seconds. The force acting on body is X newton, where X has
a value equal to
Answers
Answer:
use the formula
F = ma
acceleration = v-u/t
a = 9-3/2
a = 3m/sec²
now placing values in above force formula
Force = 4×3
F = 12 N
Explanation:
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Given : A body of mass 4 kg, initially moving straight horizontally at 3 m/s, is pushed uniformly in the same direction of its motion and its velocity becomes 9 m/s in 2 seconds.
The force acting on body is X newton
To Find : Value of X
Solution:
Initial Velocity = 3 m/s
Velocity after 2 secs = 9 m/s
V = u + at
=> 9 = 3 + a(2)
=> 6 = 2a
=> 3 = a
=> a = 3
acceleration = 3 m/s²
Force = Mass * acceleration
=> F = ma
m = 4 kg
=> F = 4 * 3
=> F = 12 N
Force is X newton
X = 12
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