Physics, asked by punitak2011, 6 months ago

A body of mass 4 kg, initially moving straight horizontally at 3 m/s, is pushed
uniformly in the same direction of its motion and its velocity becomes 9 m/s in 2
seconds. The force acting on body is X newton, where X has a value equal to​

Answers

Answered by amitnrw
0

Given : A body of mass 4 kg, initially moving straight horizontally at 3 m/s, is pushed uniformly in the same direction  of its motion and its velocity becomes 9 m/s in 2 seconds.

The force acting on body is X newton

To Find : Value of X

Solution:

Initial Velocity = 3 m/s

Velocity after 2 secs =  9 m/s

V = u + at

=> 9 = 3 + a(2)

=> 6 = 2a

=> 3 = a

=> a = 3  

acceleration = 3 m/s²

Force = Mass * acceleration

=> F = ma

m = 4 kg

=> F = 4 * 3

=> F = 12 N

Force is X newton

X  = 12

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