Question

A body of mass 4 kg is dropped from a height of 1 m. Its KE as it touches the ground is (g = 10 m/s2):

(a) 40 N
(b) 40 J
(c) 40 kg f
(d) 40 N/m
the blanks​

Answer 1

Answer:

200J

Explanation:

KE = 1/2*M*V^2

Substituting the Values

KE = 1/2*4*10^2

KE = 2*10^2

KE = 200J