Question

A body of mass 4 kg is dropped from a height of 20 m. Calculate the initial momentum and the momentum just before it strikes the ground. (g = 10 m / s 2 )​

Answer 1

Answer :-

Given:-

Mass (m) = 4 Kg

Initial velocity (u) = 0 m/s

Acceleration (a) = 10 m/s²

Distance (s) = 20 m

Initial momentum (mv):

⟹ p = 4 Kg × 0 m/s

⟹ p = 0 Kgm/s

Using third equation of motion:

⟹ v² = u² + 2as

⟹ v² = 0² + 2(10)(20)

⟹ v² = 400

⟹ v = √400

⟹ v = 20 m/s

Final momentum (mu):

⟹ p = 4 Kg × 20 m/s

⟹ p = 80 Kgm/s

∴ Initial and final momentum of the body is 0 Kgm/s and 80kgm/s respectively.

Answer 2

QUESTION:-

A body of mass 4 kg is dropped from a height of 20 m. Calculate the initial momentum and the momentum just before it strikes the ground. (g = 10 m / s²)

EXPLANATION:-

• Mass(m)=4 kg
• Height(s)=20 m
• Acceleration(a)=10 m/s²
• Initial velocity(u)=0 m/s
• Initial momentum=?
• Momentum just before body strikes=?

Initial momentum (mv):-

⟹ p = 4 Kg × 0 m/s

⟹ p = 0 Kgm/s

Now to calculate the final momentum we will calculate the final velocity

Let's use 3rd equation of motion;-

⟹ v² = u² + 2as

⟹ v² = 0² + 2(10)(20)

⟹ v² = 400

⟹ v = √400

⟹ v = 20 m/s

NoFinal momentum (mu):

⟹ p = 4 Kg × 20 m/s

⟹ p = 80 Kgm/sw let's calculate the final momentum:-

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