Question

A body of mass 4 kg is hanged at the lower end of a spring balance whose upper end is fixed at the ceiling of a lift. If the moves up with an acceleration of 6 m/s, the reading of the spring balance is

Answer 1

Given ,

m = 4 kg

a = 6 m / s

now by the relation ,

F = m × a

F = 4 kg × 6 m / s

F = 24 N

READING OF THE SPRING BALANCE = FORCE EXERTED BY THE BODY ( WEIGHT OF THE BODY )

.: READING OF SPRIN BALANCE = 24 N OR 2.4 kg OR 2400 g





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Answer 2

Answer: 64N

Explanation:

a = 6

m = 4kg

Force, F = ma = 24N

Tension on Spring = 4 × 10 = 40 N

Balance of spring = 40 + 24 = 64N