Question

a body of mass 4 kg is placed on a smooth inclined plane of angle 60°. The horizontal force to be applied to move up the plane with 2m/s² is? (g=10m/s²)

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Answer 1

Answer:

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Answer 2

Answer:

We have to find the horizontal force applied to move up the plane.

Explanation:

Given:

m = 4kg

θ = 60°

a = 2 m/s²

Calculation:

Here we can see that the horizontal force is applied to move up the plane with an acceleration. When it inclined from the surface gravity component comes into the picture and  it is equal to gsinθ.

Hence force F = m(gsinθ-a)

                     F = 4(10sin(60°)-2)

                     F= 4(8.66-2)

                     F = 4×6.66

                     F = 26.64 N

Result:

The horizontal force is equal to 26.64N