A body of mass 4 Kg moving on a horizontal surface with an initial velocity of 6m/s ,comes to rest after 3 second. If one wants to keep the body moving on the same surface with the velocity of 6m/s the force required. A body of mass 4 Kg moving on a horizontal surface with an initial velocity of 6m/s ,comes to rest after 3 second. If one wants to keep the body moving on the same surface with the velocity of 6m/s the force required
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Answer:
Given:
m=4kg
u=6m/s
v=0
t=3s
We know,
F=ma
F=m(v-u)/t [since a=v-u/t]
F=4*(0-6)/3
F=4*(-2)
F= -8N
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