a body of mass 40 g is moving with a constant velocity of 2 cm per second on a horizontal frictionless table. the force on the body in dynes is
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Force will be 0 as velocity is constant and hence acceleration is 0 therefore as F=ma and as a is 0 therefore F= m×0=0
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net force on the body will be zero because body is moving with constant velocty
acceleratio = rate of change of velocity = 0
F = ma = 40 × 0 = 0 dynes
acceleratio = rate of change of velocity = 0
F = ma = 40 × 0 = 0 dynes
shree7b7:
so that body comes in rest after 2 seconds
here value of velocity is given 2times we solve for next one in which only the velocity is given that is 4m/s so if we solve for it then the force become 0 but it is not 0. why
means one time intial velocity is given
please write the question
and in next only velocity is given
its intial or final
my question is same
the above one question
change in velocity = ( 2v - v ) = v
a = v / t
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