A body of mass 40 kg is deragged 8 m on a Smoth horizontal surface in 10 second with a constant velocity by a constant forces of 20 Newton calculate the workdone kinetic energy and power.
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M=40kg F=20N t=10s
Friction force =μmg=0.2∗40∗10=80N
Net force in forward direction =20−80=60N
So acceleration =a=Force/m=60/2=30m/s²
Initial speed =u=0
Distance traveled =s=ut+1/2at²=0+1/2∗30∗10²=0.000166m
Work done by F=F∗s=20∗0.00016=0.0032kJ
Work done by Friction force =−30∗0.0032=−0.096kJ (heat dissipated)
The kinetic energy of the body =1/2mv²=1/2m(2as)
=2∗30∗0.00016=0.0096kJ
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