Question

a body of mass 40 kg is suspended with the help of two strings as shown in the given fig. find tension T1 and T2
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Answer 1

Answer:

here is your answer hope it helps

Answer 2

ANSWER:

The tension on wire OA and OB is taken as $\mathrm{T}_{1}, \mathrm{T}_{2}=200 \mathrm{N}, 200 \sqrt{3} \mathrm{N}$

EXPLANATION:

The mass of the ball hanging from the two strings is 40 kg, the tension on the strings are taken as$\mathrm{T}_{1}, \mathrm{T}_{2}$

The gravitational force of acceleration is taken as $10 \mathrm{m} / \mathrm{sec}^{2}$

Now taking the strings OA and OB, therefore, the tension of the strings are

Now using Lami’s Law we get the value of tension holding the ball as  

$\frac{T_{1}}{\sin 120}=\frac{T_{2}}{\sin 150}=\frac{400}{\sin 90}$

$T_{1}=\frac{400 \times \sin 120}{\sin 90}=200 \sqrt{3}$

$T_{2}=\frac{400 \times \sin 150}{\sin 90}=200$

Therefore, the tension on wire OA and OB is taken as $\mathrm{T}_{1}, \mathrm{T}_{2}=200 \mathrm{N}, 200 \sqrt{3} \mathrm{N}$