Question

A body of mass 40 kg, moves with a uniform velocity under the action of a force 50N a surface. If a force of 70N now acts on the same body in die Same direction as that of 50N, moving on the same surface, the acceleration of the body is​

Answer 1

Answer:

In a previous part of Lesson 1, work was described as taking place when a force acts upon an object to cause a displacement. When a force acts to cause an object to be displaced, three quantities must be known in order to calculate the work. Those three quantities are force, displacement and the angle between the force and the displacement. The work is subsequently calculated as force•displacement•cosine(theta) where theta is the angle between the force and the displacement vectors. In this part of Lesson 1, the concepts and mathematics of work will be applied in order to analyze a variety of physical situations

Explanation:

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Answer 2

Answer:

7/4 m/s^2

Explanation:

we know that , F=M.A

so,A= F/A

GIVEN, F=70N

M=40 KG

SO ,, calculation is A=70/40 =7/4