Question

A body of mass 40g is thrown vertically upwards with an initial velocity 35m/s.
[ g = 10 ms-2]. Calculate-
i) the maximum height reached by the body. ii) the distance travelled and the displacement from the ground after 5 second [

Answer 1

Answer:

I don't know I can't help you

Answer 2

Explanation:

Given that Initial velocity, u = 40 m/s, Final velocity, v = 0 m/s.

Acceleration due to gravity, g = 10m/s2 (downward motion).

Maximum height, s = H.

As the body is thrown upward a = -g the relation v2=u2−2as gives v2=u2−2aH, we have,

H = 2gu2−v2=2(10m/s2)40m/s2−02=201600=80m.

If a stone is thrown vertically upward, it returns to its initial position after achieving maximum height.

so, the net displacement = Difference of positions between initial and final positions = 0.

Total distance covered = 80 m + 80 m = 160 m.

Hence, the displacement is 0 and the total distance covered is 160 m.