Question

A body of mass 4kg is accelerated upon by a constant force, travels a distance of 5 m in the first ,second and a distance of 2 m in the third second. The force acting on the body is?

Answer 1

Answer:10N

Explanation:

f=ma=4a

u+1/2a(2n-1)=5

u+1/2a=5....(1)

u+1/2a(5)=2

u+5a/2=2...(2)

subtracting 2 from 1

2a=5

a=5/2

f=10n