Question

A body of mass 4kg is accelerated upon by a constant force, travels a distance of 5 m in the first ,second and a distance of 2 m in the third second. The force acting on the body is?

Answer 1

hey buddy find answer by formula F=Ma

Answer 2

Answer:

answer is 6N buddy

Explanation:

bro coz

5=ut+a(22)

=u+a/s +S3

u(t3+t2)+a(t32-t22)

2=u+2.5a

2a=a-1.5

SoF=ma

6N

Hope it helps

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