A body of mass 4kg is drop from a height of 100mtr calculate it's velocity when the body reaches
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In this question there is no use of mass,
For body 1:
Height = 100m
initial velocity = 0m/s
acceleration due to gravity = 10m/s^2
Therefore, we use the formula,
s = ut + 1/2 gt^2
100 = 1/2 10 t2
Therefore, t = 10v2seconds
For body2:
Height = 50m
u = 0m/s
g = 10m/s^2
Using formula we get,
time = v10seconds
Hope this helps you...
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