Physics, asked by aryansinghi88, 11 months ago

A body of mass 4kg is moving with the velocity of 5m/s, a force of 12N is applied on it. What will be it's velocity after 1sec.​

Answers

Answered by Pragyaanly
4

Answer:

m=4 kg

initial velocity or u = 5m/s

force=12N

Time = 1 sec

FIRST WE WILL FIND AccN or Acceleration

F=ma

12=4a

a=3 m/sec×sec

v =u+at

v= 5+3×1

v=15 Velocity or 15 m/sec Is the Answer

Explanation:

Just follow motion in one dimension rule and find acceleration and find velocity by v=u+at

SUPER EASY FOLLOW PLZ..

Answered by kmousmi293
0

Answer:

The final velocity of the object after 1 second will be 8 m/s.

Explanation:

This problem can be resolved by applying the equation:

F = ma

where m is the object's mass, an is its acceleration, and F is the object's net force of action.

First, we can calculate the acceleration of the object using the given values of force and mass:

a = F/m

a =\frac{12 N}{4 kg}

a = 3 m/s^{2}

Next, we can use the following equation of motion to find the final velocity of the object after 1 second:

v = u + at

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Substituting the given values, we get:

v = 5 m/s + (3 m/s^{2})(1 s)

Simplifying, we get:

v = 5 m/s + 3 m/s

v = 8 m/s

Therefore, the final velocity of the object after 1 second will be 8 m/s.

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