A body of mass 4kg is moving with the velocity of 5m/s, a force of 12N is applied on it. What will be it's velocity after 1sec.
Answers
Answer:
m=4 kg
initial velocity or u = 5m/s
force=12N
Time = 1 sec
FIRST WE WILL FIND AccN or Acceleration
F=ma
12=4a
a=3 m/sec×sec
v =u+at
v= 5+3×1
v=15 Velocity or 15 m/sec Is the Answer
Explanation:
Just follow motion in one dimension rule and find acceleration and find velocity by v=u+at
SUPER EASY FOLLOW PLZ..
Answer:
The final velocity of the object after 1 second will be 8 m/s.
Explanation:
This problem can be resolved by applying the equation:
F = ma
where m is the object's mass, an is its acceleration, and F is the object's net force of action.
First, we can calculate the acceleration of the object using the given values of force and mass:
a = F/m
a = 3 m/
Next, we can use the following equation of motion to find the final velocity of the object after 1 second:
v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
Substituting the given values, we get:
v = 5 m/s + (3 m/)(1 s)
Simplifying, we get:
v = 5 m/s + 3 m/s
v = 8 m/s
Therefore, the final velocity of the object after 1 second will be 8 m/s.
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