A body of mass 4kg moves under the action of a force
F=4i+(12t²)j N
u=(2i+j+2k) m/s
Find the work done by the force in 1 sec?
Answers
see the attachment mate ✌️☺️
Answer:
hiii
your answer is here !
Explanation:
Work = Force × distance.
In 1 second, the force will be:
4i + 12j + 0k, here we include k since the velocity has k and when we put zero k it does not change the value of the force.
The distance moved in one second will be :
2i + i + 2k
We see that this is a vector.
We will therefore use cross product to get the product of the two vectors.
We first write it in matrix form that is a combination of the two vectors with the leading row having I, j, k respectively.
We then find the determinant of the matrix including the leading row.
Since it forms a three by three matrix, we will use cofactor expansion to get the determinant.
When we do this we get 24i - 8j - 20k
Find calculations in the image.
follow me !
