Question

A body of mass 4kg moves with a velocity of 10m/s collide elastically with
another body of mass 8kg at rest. Then the velocity of 8kg body after collision is​

Answer 1

$ANSWER</p><p></p><p>Given,</p><p></p><p></p><p>m=4kg</p><p></p><p></p><p>u=10m/s</p><p></p><p></p><p>t=1.5sec</p><p></p><p></p><p>Lets consider the velocity of body after collision is v.</p><p></p><p></p><p>Impulsive force and momentum relation is,</p><p></p><p></p><p>I=F×t=ΔP. . . . .(1)</p><p></p><p></p><p>From the given graph area under the graph is equal to impulse,</p><p></p><p></p><p>The area under the graph = area of trapezium.</p><p></p><p></p><p>A=I=21(a+b)h</p><p></p><p></p><p>I=21(1.5+0.5)×40=40Ns</p><p></p><p></p><p>equation (1),</p><p></p><p></p><p>I=m(u−v)=40</p><p></p><p></p><p>4(10−v)=40</p><p></p><p></p><p>40−4v=40</p><p></p><p></p><p>4v=0</p><p></p><p></p><p>v=0m/s</p><p></p><p></p><p>$

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