a body of mass 4kg moving with uniform velocity of 5m / s. it is acted upon by a free of 12 neuton. what will be its velocity after 1 second
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Question should be
A body of mass 4kg moving with uniform velocity of 5m/s. it is acted upon by a force of 12N. What will be its velocity after 1 second?”
Answer:
F = ma
F = m (v - u) / t ………[∵ Acceleration = Rate of change of velocity]
12 = 4 (v - 5) / 1
v = (3 + 5) m/s
v = 8 m/s
Velocity of body after 1 second will be 8 m/s
A body of mass 4kg moving with uniform velocity of 5m/s. it is acted upon by a force of 12N. What will be its velocity after 1 second?”
Answer:
F = ma
F = m (v - u) / t ………[∵ Acceleration = Rate of change of velocity]
12 = 4 (v - 5) / 1
v = (3 + 5) m/s
v = 8 m/s
Velocity of body after 1 second will be 8 m/s
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4
Answer:
Explanation:
Let mass of rope = mr = 0.5 kg, mass of block = mb = 4 kg, force applied = F = 9 N
Let the tension in the string be T
Common acceleration of the system, ac = F÷(mr+mb) = 9/4.5 = 2 m/s2
For the block to be moving with this acceleration, tension, T = mb.ac = 4*2 = 8 N.
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