Question

a body of mass 4kg moving with velocity 5m\s.A force of 12n is applied. what will be it's velocity after 1second
​

Answer 1

m=4kg

v=5m/s

F=12N

F=ma(acceleration = rate of change of velocity)

F=m(v-u)/t

=>12=4(v-5)/1

=>4(v-5)/1=12

=>4v-20/1=12

=>4v-20=12

=>4v=32

=>v=32/4

=>v=8m/s

Answer 2

$\huge\purple{ \underline{ \boxed{\mathbb{\red{QUESTION : }}}}}$

A body of mass 4 kg is moving with the velocity of 5 m/s, a force of 12 N is applied on it. What will be it's velocity after 1 sec.

$\huge\purple{ \underline{ \boxed{\mathbb{\red{ANSWER : }}}}}$

Final velocity of body = 8 m/s

$\huge\purple{ \underline{ \boxed{\mathbb{\red{EXPLANATION : }}}}}$

$\green{ \large \underline{ \mathbb{\underline{GIVEN : }}}}$

Mass of body ( m ) = 4 kg

Force ( F ) = 12 N

Time taken ( t ) = 1 s

Initial velocity ( u ) = 5 m/s

$\green{ \large \underline{ \mathbb{\underline{TO \: FIND : }}}}$

Final velocity of body .

$\green{ \large \underline{ \mathbb{\underline{FORMULAS \: USED : }}}}$

$\purple{ \boxed{ \bf a = \frac{v - u}{t} }}$

$\purple{ \boxed{ \bf F = ma}}$

$\green{ \large \underline{ \mathbb{\underline{SOLUTION: }}}}$

$\displaystyle \sf \longrightarrow F = ma \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \sf \longrightarrow F = m \bigg( \frac{v - u}{t} \bigg) \: \: \: \: \: \: \\ \\ \displaystyle \sf \longrightarrow F = \frac{m(v - u)}{t} \: \: \: \: \: \: \: \: \\ \\ \displaystyle \sf \longrightarrow F = \frac{mv - mu}{t} \: \: \: \: \: \: \: \: \\ \\ \displaystyle \sf \longrightarrow 12 = \frac{4(v) - 4(5)}{1} \: \\ \\ \displaystyle \sf \longrightarrow 12 = 4v - 20 \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \sf \longrightarrow 4v - 20 = 12 \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \sf \longrightarrow 4v = 12+ 20 \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \sf \longrightarrow 4v = 32 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \sf \longrightarrow v = \frac{32}{4} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \ \displaystyle \sf \longrightarrow v = 8 \: m {s}^{ - 1} \: \: \: \: \: \: \: \: \: \:$

$\purple{\boxed{\begin{array}{l} \sf{Final \: velocity \: of \: body = 8 \: m {s}^{ - 1}} \end{array}}}$

$\green{ \large \underline{ \mathbb{\underline{KNOW\:MORE: }}}}$

• Acceleration

Acceleration is the rate at which velocity changes with time .

• Initial Velocity

Initial velocity is the velocity of the object before the effect of acceleration .

• Final Velocity

Final velocity is the velocity of the object after the effect of acceleration .

• Force

Force is the push or pull on an object with mass that causes it to change its velocity.

$\Large{\purple{\boxed{\begin{array}{l} \textsf{Equations of motion : } \\ \\ \textsf{v = u + at} \\ \\ \displaystyle\textsf{s = ut + \sf\frac{1}{2}a {t}^{2} } \\ \\ \sf {v}^{2} - {u}^{2} = 2as \end{array}}}}$