Question

A body of mass 4kg moving with velocity of 2.5m/s collides with a stationary body of mass0.2kg. if the two bodies stick together after collision. Calculate their common velocity after impact

Answer 1

Explanation:

Taking the 2 bodies as an isolated system,

Law of conservation of momentum tells us that the total momentum will remain constant.

According to the law,

m1u1 + m2u2 = m1v1 + m2v2

But in this case, the bodies stick after collision. Since they are sticking,

Their total mass after sticking = 4 + 0.2

= 4.2 kg

Now,

m1u1 + m2u2 = m3v3

=> 4 x 2.5 + 0.2 x 0 = 4.2 x v3

=> v3 = 10 / 4.2

=> velocity after sticking = 2.38 m/s approx.

Answer 2

Hope it helps! Please refer to the attachment.

I haven't solved it on my own. I took help from aditya012 who solved it. Thanks to him.