Question

A body of mass 4kg weight 4.8kg when suspended in moving lift

Answer 1

Just use the concept of pseudo force for the body inside lift .

Let lift moves upward wiz acc. A so for body in FBD equ. Will be m(gplus a) = 4.8. Solve it for a . Acc. Of lift will come out to be 8.6 m/s downwards
hope its help u