A body of mass 4m is lying in x-y plane at rest
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From the law of conservation of momentum,Magnitude of the momentum of heavier piece of mass 2m = Magnitude of the vector sum of moemntum of each peice of mass m
(2m)v'=underroot (mv)sq+(mv)sq
=2√mv(2)v'
=2√vv'=underroot vsq.
KE generated:
KE =1/2mvsq.+1/2mvsq.+1/2(2m)(v')sq.
=1/2(mvsq.+mvsq.+(2m)(vsq./2))
=1/2(3mvsq)
(2m)v'=underroot (mv)sq+(mv)sq
=2√mv(2)v'
=2√vv'=underroot vsq.
KE generated:
KE =1/2mvsq.+1/2mvsq.+1/2(2m)(v')sq.
=1/2(mvsq.+mvsq.+(2m)(vsq./2))
=1/2(3mvsq)
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