A body of mass 4m lying in xy plane at rest. It suddenly explodes into 3 pieces each of mass m move perpendicular to each other with equal speeds v . The total K.E. generated due to explosion is
a) mv²
b)3/2 mv²
c)2mv²
d)4mv²
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Answered by
195
By law of conservation of momentum
magnitude of the momentum of heavier piece of mass 2 m
Magnitude of the vector sum of momentum of each piece of mass m
2m v' = √ (mv)² + (mv)²
2m v' = √2 mv
2 v' = √2 v
v' = v /√2
KE generated
KE = 1/2 mv² + 1/2 mv² + 1/2 (2m) (v')²
KE = 1/2 ( mv² + mv² + 2m (v)²/ 2 )
KE = 1/2 (3 mv²)
KE = 3/2 mv²
magnitude of the momentum of heavier piece of mass 2 m
Magnitude of the vector sum of momentum of each piece of mass m
2m v' = √ (mv)² + (mv)²
2m v' = √2 mv
2 v' = √2 v
v' = v /√2
KE generated
KE = 1/2 mv² + 1/2 mv² + 1/2 (2m) (v')²
KE = 1/2 ( mv² + mv² + 2m (v)²/ 2 )
KE = 1/2 (3 mv²)
KE = 3/2 mv²
Answered by
60
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