Question

A body of mass 5 gm is executing s.H.M. About a point with amplitude 10 cm. Its maximum velocity is 100 cm/sec. Its velocity will be 50 cm/sec at a distance

Answer 1

Given that

Mass of the body= 5 gm

amplitude, a=10 cm

Maximum velocity= 100 cm/sec

if a body execute S.H.M.,

Maximum velocity= a*omega        (where omega is an angular velocity of the body)

So,

Maximum velocity= a*omega= 100

omega= 100/10= 10 per sec

As we know,

v= omega*(a^2-y^2)^(1/2)

For v=50

50=10(10^2-y^2)^(1/2)

(10^2-y^2)^(1/2)=5

Squaring both sides

100-y^2=25

y^2=100-25=75

Taking square root both side, we get:

y=8.7

Therefore, the velocity of the body will be 50cm/sec at the distance of 8.7cm

Answer 2

Heya mate,

Refer to the attachment for your answer....

Hope it works (◍•ᴗ•◍)