A body of mass 5 kg falls from a height of 10m to 4m calculate the loss in potential energy of the body, and the total energy possessed by the body at any instant.
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Answered by
5
As-Salamu-Alykum
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P.E =mgh
H =10_4=6m
m=5kg
P.E = 5× 10×4
P.E= 200J ---- this is loss in P.E
Loss in P.E = Gain in K.E
200 =200
So total energy = P.E + K.E
Total energy = 200 +200=400J
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INSHALLAH it will help U
__________
P.E =mgh
H =10_4=6m
m=5kg
P.E = 5× 10×4
P.E= 200J ---- this is loss in P.E
Loss in P.E = Gain in K.E
200 =200
So total energy = P.E + K.E
Total energy = 200 +200=400J
__________
INSHALLAH it will help U
Answered by
12
Total energy = mgh
here ' h' is initial hieght.
therefore total energy = 5 × 10 × 10
= 500 j : at any instant
loss of potential energy = mg(h - h*)
h : initial height
h*: final height
therefore ; 5 × 10 ( 10 - 4 )
=300 j
this is loss in potential energy
here ' h' is initial hieght.
therefore total energy = 5 × 10 × 10
= 500 j : at any instant
loss of potential energy = mg(h - h*)
h : initial height
h*: final height
therefore ; 5 × 10 ( 10 - 4 )
=300 j
this is loss in potential energy
kumarsumittiptip:
thank u
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