Question

A body of mass 5 kg falls from rest from a height 10 m from earth's surface. The kinetic energy of the body on the earth's surface will be ( if g = 9.8 m/ sec^2):

a) 490 joule
b) zero
c) 50 joule
d) 49 joule

Answer 1

Answer:

Explanation:

Using conservation of energy

We can write KE+PE=constant

Therefore

KE(h)+PE(h)=KE(at surface)+PE(at surface)

0+mgh=KE(at surface)+0

5×9.8×10=KE

KE=490joule